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1.000=20z^2
We move all terms to the left:
1.000-(20z^2)=0
We add all the numbers together, and all the variables
-20z^2+1=0
a = -20; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-20)·1
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{5}}{2*-20}=\frac{0-4\sqrt{5}}{-40} =-\frac{4\sqrt{5}}{-40} =-\frac{\sqrt{5}}{-10} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{5}}{2*-20}=\frac{0+4\sqrt{5}}{-40} =\frac{4\sqrt{5}}{-40} =\frac{\sqrt{5}}{-10} $
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